Shooting up/down hill question
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pvauto
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Shooting up/down hill question
I'm new here and so far have got a lot of info off this site. Just last week I took out my AR in 223 and was shooting in like a 40deg angle about 240yrds. I have my gun dialed at a 50/200yrd zero but it was hitting about 5-6" high and drifted due to the wind (55gr boolits). My question is how was it hitting so high when it should be dropping? I'm new to hunting and doubt il ever take a shot past 100 but with a variation like that it can be a difference of a clean kill to even a miss. I have a lot of time shooting at p2k so I know it's accurate. On a side note I'm from east county San Diego and I want to start shooting long distances and maybe somebody can be somewhat a mentor? I have a 300 win mag that I would love to be able to stretch her legs
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Re: Shooting up/down hill question
When shooting at an angle either up angle or down angle), you are reducing the effect of gravity on the bullet.
Gravity pulls towards the earth so the effect on the bullet is strongest when your billet is flying parallel to the earth.
Any ballistic calculator will factor in the angle-of-fire for you.
There are also quick and dirty methods to adjust your dial for angles using an angle cosine chart or indicator mounted on your rifle.
The cosine gives you a percentage of adjustment.
You can either scale the distance to target, or you can scale your amount of elevation dial.
As an example, a 45 degree angle gives a 50% correction factor.
If you need to dial 0.6 mils to be on your 240yd target on level ground, you would dial only 0.3 mils to be on your 240yd target when the target is 45degrees above or below you.
Gravity pulls towards the earth so the effect on the bullet is strongest when your billet is flying parallel to the earth.
Any ballistic calculator will factor in the angle-of-fire for you.
There are also quick and dirty methods to adjust your dial for angles using an angle cosine chart or indicator mounted on your rifle.
The cosine gives you a percentage of adjustment.
You can either scale the distance to target, or you can scale your amount of elevation dial.
As an example, a 45 degree angle gives a 50% correction factor.
If you need to dial 0.6 mils to be on your 240yd target on level ground, you would dial only 0.3 mils to be on your 240yd target when the target is 45degrees above or below you.
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thegiff
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Re: Shooting up/down hill question
45° is .7 correction, so .6 mil horizontal = .42 at 45°
60° is .5 correction, so .6 mil horizontal = .3 mil at 60°
60° is .5 correction, so .6 mil horizontal = .3 mil at 60°

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Re: Shooting up/down hill question
/\ /\ /\ Damn Asians.
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pvauto
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Re: Shooting up/down hill question
ok im slightly loss lol so as of now i think i have to take 45*and do cos 45* and that equals the correction of .7 so what do i do with that now? my scope is a burris fullfield 2 that uses moa
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Re: Shooting up/down hill question
Take your normal elevation and times it by .7. Example I'm shooting my 308 at a target 1000 yards away at an angle of 45*. My normal dope is 9.6 mils. So it would be 9.6x.7=6.7. I would dial 6.7 mils on my scope and take the shot.pvauto wrote:ok im slightly loss lol so as of now i think i have to take 45*and do cos 45* and that equals the correction of .7 so what do i do with that now? my scope is a burris fullfield 2 that uses moa
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Re: Shooting up/down hill question
MOA version is the same just MOA.
34.5 x .7 = 24.15 so dial 24.25 MOA
34.5 x .7 = 24.15 so dial 24.25 MOA
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thegiff
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Re: Shooting up/down hill question
The best way is to correct the distance with the cosine of the angle. So, if you range 600 yards line of sight, and you shoot up or downhill 45°, then the drop range is 600*cos45° = 424 yards. Then, use the 424 yard number against your drop chart.
The end result is that the bullet doesn't drop as far as your line of sight distance shows, so you need to aim lower or dial less drop.
However, windage corrections are for line of sight, so use the 600 yard windage dope for your wind.
The end result is that the bullet doesn't drop as far as your line of sight distance shows, so you need to aim lower or dial less drop.
However, windage corrections are for line of sight, so use the 600 yard windage dope for your wind.

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rksimple
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Re: Shooting up/down hill question
Wrong.thegiff wrote:The best way is to correct the distance with the cosine of the angle.
http://www.exteriorballistics.com/ebexp ... icle1.html" onclick="window.open(this.href);return false;
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Re: Shooting up/down hill question
If you are indeed shoot in at a 40 degree angle, either up or down, the Line of Sight distance is 240 yards, the Horizontal distance would be 184 yards. Gravity acts only on the horizontal distance. The greater the angle, the less Horizontal distance is for gravity to act on the bullet.
This is not taking into account the effect of gravity on the terminal velocity.
This is not taking into account the effect of gravity on the terminal velocity.
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Re: Shooting up/down hill question
rksimple wrote:
Wrong.
http://www.exteriorballistics.com/ebexp ... icle1.html" onclick="window.open(this.href);return false;
Good reading material. Thank you.
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Mobius38
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Re: Shooting up/down hill question
My head hurts!
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To many words need pictures!
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pvauto
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Re: Shooting up/down hill question
thanks for the replies! i definitely have some homework to do lol im not new to shooting but i am new to learning the science behind it. i figure the more i learn the better i can shoot. i couldnt find any of this just researching online
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thegiff
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Re: Shooting up/down hill question
I re-read the Sierra link that Ryan posted, (last looked at it a few years ago) that calc comes out way closer than the one I posted.
Equation terms are:
Drop = bullet drop relative to barrel, always a negative number
Path = bullet drop or position relative to scope crosshair
Angle (theta) in degrees
Corrected Path = abs value[Line of sight Drop] * [1 - cos (theta)] - Line of sight path
Example:
1000 yards 308
horizontal drop = -440.24"
horizontal path = -398.61
at 45° angle up:
Corrected Drop = 440.24*[1-cos45] - 398.6 = -269.66"
I've edited this post a couple times... Looking through sierra's equation, they are using a drop number that is not output with jbm's normal output. The drop number is from the barrel relative to itself and not to the scope, and is always a negative number. You also need the drop relative to the scope crosshair.
This would require another set of numbers on a dope chart, or of course would be much easier with a ballistics app.
Equation terms are:
Drop = bullet drop relative to barrel, always a negative number
Path = bullet drop or position relative to scope crosshair
Angle (theta) in degrees
Corrected Path = abs value[Line of sight Drop] * [1 - cos (theta)] - Line of sight path
Example:
1000 yards 308
horizontal drop = -440.24"
horizontal path = -398.61
at 45° angle up:
Corrected Drop = 440.24*[1-cos45] - 398.6 = -269.66"
I've edited this post a couple times... Looking through sierra's equation, they are using a drop number that is not output with jbm's normal output. The drop number is from the barrel relative to itself and not to the scope, and is always a negative number. You also need the drop relative to the scope crosshair.
This would require another set of numbers on a dope chart, or of course would be much easier with a ballistics app.

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thegiff
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Re: Shooting up/down hill question
OK, I've screwed around with JBM to make it output some data that could be used in the sierra equation to get a good angle correction, here is an example:
Taking my .243 at 2940fps, 1000 yards
0°, drop relative to scope = 296.5" (called "path" by sierra)
Using JBM to calculate, we find that at 45° the result should be 199.3" drop (called "path" by sierra relative to the scope
To get the "drop" data from JBM, set zero distance to 1 yard and scope height to 0", and from the resulting drop chart at 1000yd we get 334.5"
"path" = -199.3"
"drop" = -334.5"
Theta = 45°
Corrected drop (in the scope) = 334.5(1-cos45) - 199.3 = 198.5"
Taking my .243 at 2940fps, 1000 yards
0°, drop relative to scope = 296.5" (called "path" by sierra)
Using JBM to calculate, we find that at 45° the result should be 199.3" drop (called "path" by sierra relative to the scope
To get the "drop" data from JBM, set zero distance to 1 yard and scope height to 0", and from the resulting drop chart at 1000yd we get 334.5"
"path" = -199.3"
"drop" = -334.5"
Theta = 45°
Corrected drop (in the scope) = 334.5(1-cos45) - 199.3 = 198.5"
